Online Permutation and Combination Tutor

Permutations are known as an arrangement of things. The word arrangement is used, if the order of things is measured. Combination is a choice of things or objects or any other from a collection. In combination order of stuff is unrelated. Online is one of the major sources used by most of the students since it can access whenever the students need help. Tutor is a personality working in the education of others, either independently or in group.

Permutation formula: P (n, r) = (n!)/((n-r)!)

Combination formula: C (n, r) = (n!)/(r!(n-r)!)

Where, n gives number of stuffs, and r gives number of times.

Example problems for online permutation and combination tutor:

Online permutation and combination tutor - Example 1

In how many ways can 3 shirts be arranged from among 13 pens?

Solution:

This problem involves 13 shirts, chosen 3 at a time.

Permutation formula: P (n, r) = (n!)/((n-r)!)

Here, n = 13, r = 3

P (13, 3) = (13!)/((13-3)!)

= (13 * 12 * 11 * 10)/(10!)

= 1716

There are 1716 possible ways to arrange 3 shirts from among 13 shirts.

Online permutation and combination tutor - Example 2

In a bag there are 12 pens. In how many ways can 5 pens be chosen from a bag?

Solution:

This problem involves 12 pens, chosen 5 at a time.

Combination formula: C (n, r) = (n!)/(r(n-r)!) ,

Here n = 12, r = 5

C(12, 5) = (12!)/(5!(12-5)!)

= (12 * 11 * 10 * 9 * 8) /(5 * 4 * 3 * 2 * 1 )

= 792

Therefore in 792 different ways can 5 pens be chosen from 12 pens.

Online permutation and combination tutor - Example 3

Calculate the number of permutations and combinations; n = 14, r = 4.

Solution:

Permutation: P (n, r) = (n!)/((n-r)!)

Combination: C (n, r) = (n!)/(r(n-r)!)

Here, n = 14, r = 4.

P (14, 4) = (14!) /((14- 4)!)

= (14 * 13 * 12 * 11 * 10)/(10!)

= 24024

C(14, 4) = (14!)/(4(14-4)!)

= 1001

Therefore permutations = 24024, combination = 1001

Between, if you have problem on these topics Distributive Property Problems, please browse expert math related websites for more help on syllabus for class 10th cbse.

Practice Problems online permutation and combination tutor:

Problem 1: In how many possible ways can 4 bulbs be arranged from among 13 books?

Problem 2:  In a bag there are 10 yellow pencils. In how many ways can 3 pencils be chosen from a bag?

Problem 3: Calculate the number of permutations and combinations; n = 11, r = 6.

Answer: 1) 17160

2) 120

3) P = 332640, C = 462